I found this code... if (version_compare(PHP_VERSION, '5.2.0', '>=')) { $text=filter_var($text, FILTER_SANITIZE_URL); } ...to be questionable. Under what conditions would version_compare() return true, yet the filter_var() be undefined? Because that's what is happening. Thank you. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php