2010/4/27 Peter Lind <peter.e.lind@xxxxxxxxx>:
> On 27 April 2010 14:36, Juan Rodriguez Monti <juan@xxxxxxxxxxxxxxxxxxxxx> wrote:
>> Hi guys,
>> I have some issues with while.
>>
>> I have an HTML Form, that uses GET to process its contents. Then
>> there's a PHP Script that receives the data, and evaluates the fields.
>>
>> So, in some instance of the code, I do something like :
>>
>> if (empty($a) AND empty($b)) {
>>
>> echo "something";
>> echo "something";
>> echo "something";
>>
>> while ($row = sqlite_fetch_array($results,SQLITE_BOTH)) {
>>
>> And here I print some echo's to print an HTML's Table with the results
>> of the while.
>> echo "Something more";
>> echo "etc";
>>
>> }
>> } elseif (empty($c) AND empty($d)) {
>>
>> Here there is another elseif similar to the first one explained above.
>>
>> }
>>
>> I have four or five elseif's that analizes the fields of the HTML's
>> Form and then the PHP's Code do things depending of the combinations
>> of fields submited and so on.
>>
>> The problem is that if I want to add an echo saying "Come Back to
>> Index" to index.html, I'm not able to show it after the while's
>> iteration.
>>
>> The PHP code prints the table with its results taken from SQlite
>> perfectly. Also it evaluates all the conditions flawessly. However, If
>> I add a link to come back with the text "Go to Index" after the while
>> and before the } close to the next elseif, PHP prints it in the wrong
>> ubication.
>>
>> I got something like:
>>
>> TITLE
>>
>> *** Go to Index ***
>>
>> While results. This is the table containing all the results of the
>> SQlite's Query.
>>
>> If I move the echo to other part of the block, I receive so many
>> echo's as iterations the while do ( this is logical ). However I don't
>> understand why the echo is printed above the while even when I put it
>> after the while and out of the while's block.
>>
>
> Check your html for broken html table code.
>
> Regards
> Peter
Hi Peter,
That was the problem. Solved!.
Thanks,
Juan
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