On 27 April 2010 14:36, Juan Rodriguez Monti <juan@xxxxxxxxxxxxxxxxxxxxx> wrote:
> Hi guys,
> I have some issues with while.
>
> I have an HTML Form, that uses GET to process its contents. Then
> there's a PHP Script that receives the data, and evaluates the fields.
>
> So, in some instance of the code, I do something like :
>
> if (empty($a) AND empty($b)) {
>
> echo "something";
> echo "something";
> echo "something";
>
> while ($row = sqlite_fetch_array($results,SQLITE_BOTH)) {
>
> And here I print some echo's to print an HTML's Table with the results
> of the while.
> echo "Something more";
> echo "etc";
>
> }
> } elseif (empty($c) AND empty($d)) {
>
> Here there is another elseif similar to the first one explained above.
>
> }
>
> I have four or five elseif's that analizes the fields of the HTML's
> Form and then the PHP's Code do things depending of the combinations
> of fields submited and so on.
>
> The problem is that if I want to add an echo saying "Come Back to
> Index" to index.html, I'm not able to show it after the while's
> iteration.
>
> The PHP code prints the table with its results taken from SQlite
> perfectly. Also it evaluates all the conditions flawessly. However, If
> I add a link to come back with the text "Go to Index" after the while
> and before the } close to the next elseif, PHP prints it in the wrong
> ubication.
>
> I got something like:
>
> TITLE
>
> *** Go to Index ***
>
> While results. This is the table containing all the results of the
> SQlite's Query.
>
> If I move the echo to other part of the block, I receive so many
> echo's as iterations the while do ( this is logical ). However I don't
> understand why the echo is printed above the while even when I put it
> after the while and out of the while's block.
>
Check your html for broken html table code.
Regards
Peter
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