Hi guys,
I have some issues with while.
I have an HTML Form, that uses GET to process its contents. Then
there's a PHP Script that receives the data, and evaluates the fields.
So, in some instance of the code, I do something like :
if (empty($a) AND empty($b)) {
echo "something";
echo "something";
echo "something";
while ($row = sqlite_fetch_array($results,SQLITE_BOTH)) {
And here I print some echo's to print an HTML's Table with the results
of the while.
echo "Something more";
echo "etc";
}
} elseif (empty($c) AND empty($d)) {
Here there is another elseif similar to the first one explained above.
}
I have four or five elseif's that analizes the fields of the HTML's
Form and then the PHP's Code do things depending of the combinations
of fields submited and so on.
The problem is that if I want to add an echo saying "Come Back to
Index" to index.html, I'm not able to show it after the while's
iteration.
The PHP code prints the table with its results taken from SQlite
perfectly. Also it evaluates all the conditions flawessly. However, If
I add a link to come back with the text "Go to Index" after the while
and before the } close to the next elseif, PHP prints it in the wrong
ubication.
I got something like:
TITLE
*** Go to Index ***
While results. This is the table containing all the results of the
SQlite's Query.
If I move the echo to other part of the block, I receive so many
echo's as iterations the while do ( this is logical ). However I don't
understand why the echo is printed above the while even when I put it
after the while and out of the while's block.
Thanks a lot!.
Juan
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