On Sep 25, 2009, at 3:12 PM, Geert Tapperwijn <g.tapperwijn@xxxxxxxxx>
wrote:
Can't you just use the eval <http://nl2.php.net/eval> function, and
parse
the code from the include file in it?
.. or is there something I'm missing her
Because eval has risks if code gets injected into the code you mean to
run.
Bastien
Sent from my iPod
2009/9/25 Carl Furst <cfurst@xxxxxxxxxxxxxxxxxxxx>
Jim Lucas wrote:
Ashley Sheridan wrote:
On Wed, 2009-09-23 at 07:36 -0700, Jim Lucas wrote:
Mert Oztekin wrote:
Output buffering will do it.
Also I am not sure but did you try retrieving content with fopen
() ?
Something like
$file = 'invoicetable_bottom.php';
fopen("http://yoursite.com/folder/$file","r";);
http://tr.php.net/function.fopen
worth trying. Easier than output buffering
This would not work. fopen would open the file for read. What
you
would be
reading is the actual source of the document. Not the data the
script
would
output when ran.
The ob_* functions are the only way that I know of to do what
you are
asking
-----Original Message-----
From: Puiu Hrenciuc [mailto:hpuiu@xxxxxxxxx]
Sent: Wednesday, September 23, 2009 1:36 PM
To: php-general@xxxxxxxxxxxxx
Subject: Re: How to take output from an include, and
embed it
into a variable?
Hi,
The simplest way (actually the single way I know :) ) would be to
capture the output using output buffering functions, something
like
this:
// start output buffering
ob_start();
// include the file that generates the HTML (or whatever content)
include "....";
// get output buffer content
$output=ob_get_contents();
// clean output buffer and stop buffering
ob_end_clean();
// the content generated in the included file is now in $output
variable
// use it as you consider fit
.........
Regards,
Puiu
Rob Gould wrote:
I have an invoice table that is drawn on a number of pages, so
I have
all the logic in an include-file like this:
include "invoicetable_bottom.php";
However, now I'm needing to take the output from that include
file and
pass it as an email. To do that, I need to somehow take the
output
from
this include file and get it into a variable somehow. Is
there a
simple
way to do this?
Something like: $emailtcontent = include
"invoicetable_bottom.php"?
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That's just crazy talk. If you use fopen on a web URL, then it will
always return the output the script generates. That's how http
works!
Sorry, my bad. Ash is correct, the method that is suggested will
work.
But you
will need to enable options in your php.ini that are not on by
default for
security reasons, plus as Ben points out, you will need to filter
out the
scruff
that is generated to capture just the data output from your include.
Mind you that all of this also requires that the file that you are
including is
accessible via the web. It could be in a folder that is not web
accessible.
Sorry for the initial confusion!
Thanks,
Ash
http://www.ashleysheridan.co.uk
Do you have php configured to compile files? Why not just backtick
the php
-f command??
<?
$cmd = *escapeshellcmd*("/full/path/to/php -f $file");
$email_output = `$cmd`;
# do something with $email_output
?>
Seems easier than a whole http call.. can be risky if the $file
variable
can be set by user input (big no no), but other than that.. seeems
the
simplest.
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