On Wed, 2009-07-22 at 07:54 -0700, Jim Lucas wrote:
> rszeus wrote:
> > Thank you.
> >
> > What about instead test i want to insert a variable ?
> > Like
> > $id = "30";
> > $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg";
> > echo preg_replace('#(screens/)temp/(.+?)_1(_main\.jpg)#', '$1$id$3', $file);
>
> Sure that can be done. But you will need to change the second argument
> to have double quotes so it will be parsed by PHP.
>
> Then I would surround YOUR variable with curly brackets to separate it
> from the rest.
>
> echo preg_replace('#(screens/)temp/.+?_1(_main\.jpg)#',
> "$1{$id}$3",
> $file);
>
> > I am confusing " and '.
> >
> > Thank you
> >
> >
> > -----Mensagem original-----
> > De: Eddie Drapkin [mailto:oorza2k5@xxxxxxxxx]
> > Enviada: quarta-feira, 22 de Julho de 2009 14:12
> > Para: rszeus
> > Cc: php-general@xxxxxxxxxxxxx
> > Assunto: Re: Replace in a string with regex
> >
> > On Wed, Jul 22, 2009 at 9:07 AM, rszeus<rszeus@xxxxxxxxx> wrote:
> >> Hi. It Works to remove the _1 but it doesn't replace '7a45gfdi6icpan1jtb1j99o925' for 'test'
> >>
> >> Thank you
> >>
> >> -----Mensagem original-----
> >> De: Eddie Drapkin [mailto:oorza2k5@xxxxxxxxx]
> >> Enviada: quarta-feira, 22 de Julho de 2009 13:11
> >> Para: rszeus
> >> Cc: php-general@xxxxxxxxxxxxx
> >> Assunto: Re: Replace in a string with regex
> >>
> >> On Wed, Jul 22, 2009 at 8:02 AM, rszeus<rszeus@xxxxxxxxx> wrote:
> >>> Hello,
> >>>
> >>> I’m tryng to make some replacements on a string.
> >>>
> >>> Everything goês fine until the regular expression.
> >>>
> >>>
> >>>
> >>> $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg";
> >>>
> >>> echo $a = str_replace(array(7a45gfdi6icpan1jtb1j99o925,
> >>> 'temp/',’_([0-9])’), array(“test”,"",””), $file)
> >>>
> >>>
> >>>
> >>> The idea is to remove /temp and the last _1 from the file name..but i’m only
> >>> getting this:
> >>>
> >>> screens/test_1_main.jpg
> >>>
> >>>
> >>>
> >>> I want it to be: screens/test_main.jpg
> >>>
> >>>
> >>>
> >>> Thank you
> >>>
> >>>
> >>>
> >>>
> >> If you're trying to do a regular expression based search and replace,
> >> you probably ought to use preg_replace instead of str_replace, as
> >> str_replace doesn't parse regular expressions.
> >>
> >> Try this one out, I think I got what you wanted to do:
> >>
> >> <?php
> >>
> >> $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg";
> >>
> >> echo preg_replace('#(screens/)temp/(.+?)_1(_main\.jpg)#', '$1$2$3', $file);
> >>
> >>
> >
> > In the second parameter, $2 is the string you'd want to replace to
> > test so change '$1$2$3' to '$1test$3'.
> >
> > It seems like you're having trouble with regular expressions, may I
> > suggest you read up on them?
> >
> > http://www.regular-expressions.info/ is a pretty great free resource,
> > as ridiculous as the design is.
> >
> >
>
>
>
I tested this, with the double quotes and the curly braces around the
middle argument (to avoid PHP getting confused) and it didn't recognise
the matches by the numbered $1, $3, etc. I know I'm not the op who asked
the original question, but it might help him/her?
Thanks
Ash
www.ashleysheridan.co.uk
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