On Wed, Jul 22, 2009 at 9:07 AM, rszeus<rszeus@xxxxxxxxx> wrote: > Hi. It Works to remove the _1 but it doesn't replace '7a45gfdi6icpan1jtb1j99o925' for 'test' > > Thank you > > -----Mensagem original----- > De: Eddie Drapkin [mailto:oorza2k5@xxxxxxxxx] > Enviada: quarta-feira, 22 de Julho de 2009 13:11 > Para: rszeus > Cc: php-general@xxxxxxxxxxxxx > Assunto: Re: Replace in a string with regex > > On Wed, Jul 22, 2009 at 8:02 AM, rszeus<rszeus@xxxxxxxxx> wrote: >> Hello, >> >> I’m tryng to make some replacements on a string. >> >> Everything goês fine until the regular expression. >> >> >> >> $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; >> >> echo $a = str_replace(array(7a45gfdi6icpan1jtb1j99o925, >> 'temp/',’_([0-9])’), array(“test”,"",””), $file) >> >> >> >> The idea is to remove /temp and the last _1 from the file name..but i’m only >> getting this: >> >> screens/test_1_main.jpg >> >> >> >> I want it to be: screens/test_main.jpg >> >> >> >> Thank you >> >> >> >> > > If you're trying to do a regular expression based search and replace, > you probably ought to use preg_replace instead of str_replace, as > str_replace doesn't parse regular expressions. > > Try this one out, I think I got what you wanted to do: > > <?php > > $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; > > echo preg_replace('#(screens/)temp/(.+?)_1(_main\.jpg)#', '$1$2$3', $file); > > In the second parameter, $2 is the string you'd want to replace to test so change '$1$2$3' to '$1test$3'. It seems like you're having trouble with regular expressions, may I suggest you read up on them? http://www.regular-expressions.info/ is a pretty great free resource, as ridiculous as the design is. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
