Hi. It Works to remove the _1 but it doesn't replace '7a45gfdi6icpan1jtb1j99o925' for 'test' Thank you -----Mensagem original----- De: Eddie Drapkin [mailto:oorza2k5@xxxxxxxxx] Enviada: quarta-feira, 22 de Julho de 2009 13:11 Para: rszeus Cc: php-general@xxxxxxxxxxxxx Assunto: Re: Replace in a string with regex On Wed, Jul 22, 2009 at 8:02 AM, rszeus<rszeus@xxxxxxxxx> wrote: > Hello, > > I’m tryng to make some replacements on a string. > > Everything goês fine until the regular expression. > > > > $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; > > echo $a = str_replace(array(7a45gfdi6icpan1jtb1j99o925, > 'temp/',’_([0-9])’), array(“test”,"",””), $file) > > > > The idea is to remove /temp and the last _1 from the file name..but i’m only > getting this: > > screens/test_1_main.jpg > > > > I want it to be: screens/test_main.jpg > > > > Thank you > > > > If you're trying to do a regular expression based search and replace, you probably ought to use preg_replace instead of str_replace, as str_replace doesn't parse regular expressions. Try this one out, I think I got what you wanted to do: <?php $file = "screens/temp/7a45gfdi6icpan1jtb1j99o925_1_main.jpg"; echo preg_replace('#(screens/)temp/(.+?)_1(_main\.jpg)#', '$1$2$3', $file); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
