Ron Piggott wrote:
Where $date_reference is 2009-04-18 the following code gives me a day of
1969-12-30. How do I get it to be 2009-04-17?
$previous_date = strtotime("-1 days", $date_reference);
$previous_date = date('Y-m-d', $previous_date);
echo $previous_date; outputs 1969-12-30
Ron
You need to read the strtotime page in the manual.
http://php.net/strtotime
It says that the second argument of the strtotime function is suppose to be a unix time stamp.
Is the value that you gave us for $date_reference a unix time stamp? No
Your code should be like this.
// This converts 2009-04-19 00:00:00 into 1240099200
$date_reference_unix = strtotime($date_reference);
$previous_date = strtotime("-1 days", $date_reference_unix);
$previous_date = date('Y-m-d', $previous_date);
echo $previous_date; outputs 1969-12-30
--
Jim Lucas
"Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them."
Twelfth Night, Act II, Scene V
by William Shakespeare
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