Re: DATE / strtotime

[Chris <dmagick@xxxxxxxxx>]

Ron Piggott wrote:
> Where $date_reference is 2009-04-18 the following code gives me a day of
> 1969-12-30. How do I get it to be 2009-04-17? 
>
> $previous_date = strtotime("-1 days", $date_reference); 
> $previous_date = date('Y-m-d', $previous_date);

Slightly wrong syntax.

$previous_date = strtotime("$date_reference -1 days");

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