DATE / strtotime

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Where $date_reference is 2009-04-18 the following code gives me a day of
1969-12-30. How do I get it to be 2009-04-17? 

$previous_date = strtotime("-1 days", $date_reference); 
$previous_date = date('Y-m-d', $previous_date);

echo $previous_date;   outputs 1969-12-30

Ron


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