Chris wrote: > >> The main problem is that you've never explained what you want to get >> from the query. The replies have used your code as an example and I'm >> pretty sure that's not what you want. Unless I totally mis-understand >> what you want, you have 2 options: >> >> 1. Use the 2 queries that I gave you in a previous post. >> 2. Use a subquery: >> >> $sql = "SELECT * FROM workorders WHERE AdminID = (SELECT AdminID FROM >> admin WHERE UserName = '" . >> mysql_real_escape_string($_SESSION['user']) . "')"; > > 3 - fix the join ;) > Yes, however, I'm going out on a limb here because we don't really know what he wants - he is only getting admin.AdminID, workorders.AdminID returned in all of the queries I've seen. I'm assuming that he wants some of the workorder details. -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
