Re: Making a Variable from different tables with Matching Dbfields?

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On Wed, Jan 28, 2009 at 3:43 PM, Shawn McKenzie <nospam@xxxxxxxxxxxxx>wrote:

> Shawn McKenzie wrote:
> > Terion Miller wrote:
> >> Well I'm stuck I have the AdminID but now I can't seem to use it to pull
> >> workorders with that AdminID . I couldn't get your block to work Andrew
> :(
> >>
> >> I think I'm just not using it right now that I have it...lol
> >>
> >>
> >> On Wed, Jan 28, 2009 at 2:26 PM, Andrew Ballard <aballard@xxxxxxxxx>
> wrote:
> >>
> >>> On Wed, Jan 28, 2009 at 3:18 PM, Terion Miller <
> webdev.terion@xxxxxxxxx>
> >>> wrote:
> >>>> Not sure if I'm wording this right, what I am trying to do is look in
> two
> >>>> tables, match the ID to use to pull information....
> >>>>
> >>>> Here's my code but it's not right, although it is picking up the user
> >>> from
> >>>> the session, I will also post what my variable debugging lists:
> >>>>
> >>>>    $query = "SELECT  admin.AdminID, workorders.AdminID FROM admin,
> >>>> workorders WHERE admin.UserName =   '".$_SESSION['user']."' ";
> >>>>    $result = mysql_query ($query);
> >>>>    $row = mysql_fetch_assoc ($result);
> >>>>
> >>>>    echo $row['AdminID'];
> >>>>
> >>>>    if ($row['ViewMyOrders'] == "NO") {
> >>>>        header ("Location: Welcome.php?AdminID=$AdminID&msg=Sorry, you
> do
> >>>> not have access to that page.");
> >>>>    }
> >>>>
> >>>> *Also tried this to pull just this persons orders:*
> >>>>
> >>>>    $sql = "SELECT workorders.WorkOrderID , workorders.AdminID,
> >>>> admin.AdminID FROM workorders, admin WHERE workorders.AdminID =
> >>>> admin.AdminID ";
> >>>>    $result = mysql_query ($sql);
> >>>>
> >>>> Thanks for looking, t.
> >>>>
> >>> Your first version gives you a Cartesian product containing more rows
> >>> than you are expecting. (All rows from the workorders table joined
> >>> with the row in the admin table where the username matches.) The
> >>> second version returns all rows where the AdminIDs match, but for all
> >>> users. You need to combine them:
> >>>
> >>> $sql =
> >>> "SELECT workorders.WorkOrderID , workorders.AdminID, admin.AdminID
> >>> FROM workorders, admin
> >>> WHERE workorders.AdminID = admin.AdminID
> >>>   AND admin.UserName = '" . mysql_real_escape_string($username) . "'";
> >>>
> >>>
> >>> Although I believe the preferred syntax (at least, I think it's the
> >>> preferred) is
> >>>
> >>> $sql =
> >>> "SELECT workorders.WorkOrderID , workorders.AdminID, admin.AdminID
> >>> FROM workorders
> >>>              INNER JOIN
> >>>           admin
> >>>             ON  workorders.AdminID = admin.AdminID
> >>> WHERE admin.UserName = '" . mysql_real_escape_string($username) . "'";
> >>>
> >>>
> >>> Andrew
> >>>
> >
> > I think I see what you're trying to do:
> >
> > $query = "SELECT AdminID FROM admin WHERE UserName = '"
> > . mysql_real_escape_string($_SESSION['user']) . "'";
> > $result = mysql_query($query);
> > $admins = mysql_fetch_assoc($result);
> >
> > $query = "SELECT * FROM workorders WHERE AdminID = '"
> > . $admins['AdminID'] . "'";
> > $result = mysql_query($query);
> > $workorders = mysql_fetch_assoc($result);
> >
>
> Well maybe not.  Has anyone noticed that all the proposed selects
> including the OPs are only returning AdminID and WorkOrderID?  But in
> the OPs code he's trying to use $row['ViewMyOrders']!
>
> --
> Thanks!
> -Shawn
> http://www.spidean.com
>

I have to get only the work orders associated with the adminID, I get the
pages but no orders.  and if I print my variables I am grabbing the right
adminID but it's not then going and grabbing the work orders with it.  I'm
not up on the correct phrasing, been doing this about 2 months.

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