Re: SQL syntax?

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ah...I also though it was because I didn't have a statement like where
adsize = adsize or something but I tried that and got the same error I have
been getting ...

You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near 'FROM
workorderform, WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC' at
line 2

and why does it keep saying line 2...
here is the snippet as it is now:

 $sql = "SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate, '%b.
%e, %Y %l:%i %p') AS Start_Date,
    DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ";
    $sql .= "Advertiser AS Advertiser_Name,AccountNum AS Account_Number,
Impressions AS Ad_Impressions, ";
    $sql .= "AdSize AS Ad_Size, CPM AS CPM_Rate, ";
    $sql.= "FROM workorderform, ";
    $sql .= " WHERE WorkOrderID = WorkOrderID ORDER BY StartDate DESC";


On Fri, Dec 5, 2008 at 4:14 PM, Allan Arguelles <allan@xxxxxxxxxxxxxxxx>wrote:

>  Umm.. I meant you need to put
>
> $sql .= "FROM workorderform ";
>
> between these:
>
> $sql .= "AdSize AS Ad_Size,  CPM AS CPM_Rate, ";
> $sql .= "ORDER BY StartDate DESC";
>
>
> :)
>
>
> Terion Miller wrote:
>
> On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles <allan@xxxxxxxxxxxxxxxx> <allan@xxxxxxxxxxxxxxxx>wrote:
>
>
>
>      $sql = "SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate,
>
>
>  '%b.
>
>
>  %e, %Y %l:%i %p') AS Start_Date,
>     DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ";
>     $sql .= "Advertiser AS Advertiser_Name,AccountNum AS Account_Number,
> Impressions AS Ad_Impressions, ";
>     $sql .= "AdSize AS Ad_Size,  CPM AS CPM_Rate, ";
>     $sql .= "ORDER BY StartDate DESC";
>
>
>
>  You forgot the tables, plus you have an extra comma after CPM_Rate.
>
> well I changed it to:
>
>  $sql = "SELECT workorderform.WorkOrderID AS Work_Order_ID,
> DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date,
>     DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date,
> ";
>     $sql .= "workorderform.Advertiser AS
> Advertiser_Name,workorderform.AccountNum AS Account_Number,
> workorderform.Impressions AS Ad_Impressions, ";
>     $sql .= "workorderform.AdSize AS Ad_Size,  workorderform.CPM AS
> CPM_Rate ";
>     $sql .= "ORDER BY StartDate DESC";
>
> and got the same error....
>
>
>
>
>

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