Re: SQL syntax?

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On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles <allan@xxxxxxxxxxxxxxxx>wrote:

>
> >
> >     $sql = "SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate,
> '%b.
> > %e, %Y %l:%i %p') AS Start_Date,
> >     DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ";
> >     $sql .= "Advertiser AS Advertiser_Name,AccountNum AS Account_Number,
> > Impressions AS Ad_Impressions, ";
> >     $sql .= "AdSize AS Ad_Size,  CPM AS CPM_Rate, ";
> >     $sql .= "ORDER BY StartDate DESC";
> >
>
> You forgot the tables, plus you have an extra comma after CPM_Rate.
>
> well I changed it to:
>
>  $sql = "SELECT workorderform.WorkOrderID AS Work_Order_ID,
> DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date,
>     DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date,
> ";
>     $sql .= "workorderform.Advertiser AS
> Advertiser_Name,workorderform.AccountNum AS Account_Number,
> workorderform.Impressions AS Ad_Impressions, ";
>     $sql .= "workorderform.AdSize AS Ad_Size,  workorderform.CPM AS
> CPM_Rate ";
>     $sql .= "ORDER BY StartDate DESC";
>
> and got the same error....
>
>

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