Re: SQL syntax?

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Umm.. I meant you need to put

$sql .= "FROM workorderform ";

between these:

$sql .= "AdSize AS Ad_Size,  CPM AS CPM_Rate, ";
$sql .= "ORDER BY StartDate DESC";


:)


Terion Miller wrote:
> On Fri, Dec 5, 2008 at 3:57 PM, Allan Arguelles <allan@xxxxxxxxxxxxxxxx>wrote:
>
>   
>>>     $sql = "SELECT WorkOrderID AS Work_Order_ID, DATE_FORMAT(StartDate,
>>>       
>> '%b.
>>     
>>> %e, %Y %l:%i %p') AS Start_Date,
>>>     DATE_FORMAT(EndDate, '%b. %e, %Y %l:%i %p') AS End_Date, ";
>>>     $sql .= "Advertiser AS Advertiser_Name,AccountNum AS Account_Number,
>>> Impressions AS Ad_Impressions, ";
>>>     $sql .= "AdSize AS Ad_Size,  CPM AS CPM_Rate, ";
>>>     $sql .= "ORDER BY StartDate DESC";
>>>
>>>       
>> You forgot the tables, plus you have an extra comma after CPM_Rate.
>>
>> well I changed it to:
>>
>>  $sql = "SELECT workorderform.WorkOrderID AS Work_Order_ID,
>> DATE_FORMAT(workorderform.StartDate, '%b. %e, %Y %l:%i %p') AS Start_Date,
>>     DATE_FORMAT(workorderform.EndDate, '%b. %e, %Y %l:%i %p') AS End_Date,
>> ";
>>     $sql .= "workorderform.Advertiser AS
>> Advertiser_Name,workorderform.AccountNum AS Account_Number,
>> workorderform.Impressions AS Ad_Impressions, ";
>>     $sql .= "workorderform.AdSize AS Ad_Size,  workorderform.CPM AS
>> CPM_Rate ";
>>     $sql .= "ORDER BY StartDate DESC";
>>
>> and got the same error....
>>
>>
>>     
>
>   

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