Roberto Costumero Moreno wrote:
I think the problem is easier... and also the solutions doing a "for"
instead of "foreach" are not good solutions because if the array is not
index-consecutive the loop fails.
So, if you has an array with the colors as indexes and the integer value X
as the value for that position of the array, updating is very easy.
You have an array such as:
$array = array( );
$array['blue'] = 4;
$array['orange'] = 5;
$array['green'] = 6;
....
So if you want to update the key 'orange' with a new value $new_value is as
easy as:
$array['orange'] += $new_value;
As the new value is being passed as an array so as to update it, it should
be like:
$new_value = array('orange',2);
So you have to do a foreach in the $new_value array like:
foreach ($new_value as $key => $value){
if(in_array($key,$array)){
$array[$key] += $value;
}
}
I think that solution works and is the easiest way to do it.
Cheers,
Roberto
On 01/07/2008, tedd <tedd.sperling@xxxxxxxxx> wrote:
At 9:35 AM +0100 7/1/08, Richard Heyes wrote:
Brian Dunning wrote:
Seems like it should be really simple but all the ways I can figure out
to do it are too kludgey.
It's rather easy:
for ($i=0; $i<count($arr); $i++) {
if ($arr[$i][0] == $new_array[0]) {
$arr[$i][1] += $new_array[1];
break; // Optional - means the first "orange" found will be
// updated only
}
}
--
Richard Heyes
Small correction:
for ($i=0; $i<count($arr); $i++)
{
if ($arr[$i][0] == $new_value [0])
{
$arr[$i][1] += $new_value [1];
break; // Optional - means the first "orange" found will be
// updated only
}
}
See here:
http://www.webbytedd.com/b1/array/
But, I'm not sure as to why you (Brian) would want to do that anyway.
tedd
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All of that is fine and dandy, but what if he can't change the structure
of the array?
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