I think the problem is easier... and also the solutions doing a "for"
instead of "foreach" are not good solutions because if the array is not
index-consecutive the loop fails.
So, if you has an array with the colors as indexes and the integer value X
as the value for that position of the array, updating is very easy.
You have an array such as:
$array = array( );
$array['blue'] = 4;
$array['orange'] = 5;
$array['green'] = 6;
....
So if you want to update the key 'orange' with a new value $new_value is as
easy as:
$array['orange'] += $new_value;
As the new value is being passed as an array so as to update it, it should
be like:
$new_value = array('orange',2);
So you have to do a foreach in the $new_value array like:
foreach ($new_value as $key => $value){
if(in_array($key,$array)){
$array[$key] += $value;
}
}
I think that solution works and is the easiest way to do it.
Cheers,
Roberto
On 01/07/2008, tedd <tedd.sperling@xxxxxxxxx> wrote:
>
> At 9:35 AM +0100 7/1/08, Richard Heyes wrote:
>
>> Brian Dunning wrote:
>>
>>> Seems like it should be really simple but all the ways I can figure out
>>> to do it are too kludgey.
>>>
>>
>> It's rather easy:
>>
>> for ($i=0; $i<count($arr); $i++) {
>> if ($arr[$i][0] == $new_array[0]) {
>> $arr[$i][1] += $new_array[1];
>> break; // Optional - means the first "orange" found will be
>> // updated only
>> }
>> }
>>
>> --
>> Richard Heyes
>>
>
> Small correction:
>
> for ($i=0; $i<count($arr); $i++)
> {
> if ($arr[$i][0] == $new_value [0])
> {
> $arr[$i][1] += $new_value [1];
> break; // Optional - means the first "orange" found will be
> // updated only
> }
> }
>
> See here:
>
> http://www.webbytedd.com/b1/array/
>
> But, I'm not sure as to why you (Brian) would want to do that anyway.
>
> tedd
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