Al wrote:
> Delimiters needed. Can use about anything not already in your pattern.
> "/" is very commonly used; but I like "#" or "%" generally; but, you
> can't use "%" because your pattern has it.
>
> $html = preg_replace("#%ResID#",$bookid,$html);
wont a str_replace() do just fine in this case?
// and we can do backticks too ;-)
$html = str_replace("%ResID", $bookid, `cat htmlfile`);
>
>
> Richard Luckhurst wrote:
>> Hi
>> I am in the process of porting a Perl application to PHP and I have
>> hit a snag
>> with trying to substitute test within a file. I have looked at the PHP
>> manual
>> and believe I should be using preg_replace but I have tried the
>> examples and am
>> not getting the result I would expect. I would appreciate any help in
>> getting
>> this to work.
>>
>> In Perl I have the following
>>
>> $html = `cat htmlfile`;
>> $html =~ s/%ResID/$bookid/g;
>>
>> which replaces each instance of %ResID with the contents of the
>> variable $bookid
>>
>> In PHP I have tried
>>
>> $html = `cat htmlfile`;
>> $html = preg_replace('%ResID',$bookid,$html);
>>
>> When I run this I find $html is empty rather than containing the file
>> with the
>> %ResID replaced with the contents of $bookid.
>>
>> I would appreciate any help with my understanding of preg_replace.
>>
>>
>>
>> Regards,
>> Richard Luckhurst Product Development
>> Exodus Systems - Sydney, Australia.
>> rluckhurst@xxxxxxxxxxxxx
>> Tel: (+612) 4751-9633
>> Fax: (+612) 4751-9644
>> Web: www.resmaster.com =================================================
>> Exodus Systems - Smarter Systems, Better Business
>> =================================================
>
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