Delimiters needed. Can use about anything not already in your pattern. "/" is
very commonly used; but I like "#" or "%" generally; but, you can't use "%"
because your pattern has it.
$html = preg_replace("#%ResID#",$bookid,$html);
Richard Luckhurst wrote:
Hi
I am in the process of porting a Perl application to PHP and I have hit a snag
with trying to substitute test within a file. I have looked at the PHP manual
and believe I should be using preg_replace but I have tried the examples and am
not getting the result I would expect. I would appreciate any help in getting
this to work.
In Perl I have the following
$html = `cat htmlfile`;
$html =~ s/%ResID/$bookid/g;
which replaces each instance of %ResID with the contents of the variable $bookid
In PHP I have tried
$html = `cat htmlfile`;
$html = preg_replace('%ResID',$bookid,$html);
When I run this I find $html is empty rather than containing the file with the
%ResID replaced with the contents of $bookid.
I would appreciate any help with my understanding of preg_replace.
Regards,
Richard Luckhurst
Product Development
Exodus Systems - Sydney, Australia.
rluckhurst@xxxxxxxxxxxxx
Tel: (+612) 4751-9633
Fax: (+612) 4751-9644
Web: www.resmaster.com
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