When $component_reference is 5 or 19 I don't want the echo statement to output to the screen. What is the correct syntax? What I have below isn't working. Thanks for your help. Ron if ( ($component_reference != "5") OR ($component_reference != "19") ) { echo "<li><a href=\"index.php?request=" . $request . "\">" . $component_name . "</a>"; } -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php