IF command

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When $component_reference is 5 or 19 I don't want the echo statement to 
output to the screen.  What is the correct syntax?  What I have below isn't 
working.  Thanks for your help.  Ron

if ( ($component_reference != "5") OR ($component_reference != "19") ) {
echo "<li><a href=\"index.php?request=" . $request . "\">" . 
$component_name . "</a>";
}

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