Hi, here is the code: if ( ($component_reference != "5") AND ($component_reference != "19") ) { echo "<li><a href=\"index.php?request=" . $request . "\">" . $component_name . "</a>"; } 2007/10/19, ron.php <ron.php@xxxxxxxxxxxxxxxxxx>: > When $component_reference is 5 or 19 I don't want the echo statement to > output to the screen. What is the correct syntax? What I have below isn't > working. Thanks for your help. Ron > > if ( ($component_reference != "5") OR ($component_reference != "19") ) { > echo "<li><a href=\"index.php?request=" . $request . "\">" . > $component_name . "</a>"; > } > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php