Re: IF command

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Hi, here is the code:

if ( ($component_reference != "5") AND ($component_reference != "19") ) {
	echo "<li><a href=\"index.php?request=" . $request . "\">" .
$component_name . "</a>";
}


2007/10/19, ron.php <ron.php@xxxxxxxxxxxxxxxxxx>:
> When $component_reference is 5 or 19 I don't want the echo statement to
> output to the screen.  What is the correct syntax?  What I have below isn't
> working.  Thanks for your help.  Ron
>
> if ( ($component_reference != "5") OR ($component_reference != "19") ) {
> echo "<li><a href=\"index.php?request=" . $request . "\">" .
> $component_name . "</a>";
> }
>
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