On 6/3/06, Adam Zey <azey@xxxxxx> wrote:
Rodrigo de Oliveira Costa wrote:
> I just discovered the problem I have to retrieve the output of the
> site and not the url since its dynamic. Ca I do it like retrieve the
> output of this url:
>
> www.tryout.com/1/2/
>
> And of course store it on a variable? How to do it? I founr the func
> below but couldnt understand how to make it work with a url.
>
> Thanks guys,
> Rodrigo
>
>
> ob_start();
> include('file.php'); // Could be a site here? What should I do to
> retrieve it from an url?
> $output = ob_get_contents();
> ob_end_clean();
Umm..... As I said, just use file_get_contents():
$file = file_get_contents("http://www.tryout.com/1/2/";);
Assuming allow_url_fopen is on.
If not, you could try using curl - see http://www.php.net/curl
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