I just discovered the problem I have to retrieve the output of the
site and not the url since its dynamic. Ca I do it like retrieve the
output of this url:
www.tryout.com/1/2/
And of course store it on a variable? How to do it? I founr the func
below but couldnt understand how to make it work with a url.
Thanks guys,
Rodrigo
ob_start();
include('file.php'); // Could be a site here? What should I do to
retrieve it from an url?
$output = ob_get_contents();
ob_end_clean();
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
