Hi again:
I said:
I'm trying to create a thumbnail from a jpeg stored in a long blob in mySQL.
---
-philip said:
imagecreatefromjpeg takes a *filename* not the actual contents of
the file itself.
Yes, you are correct that in the statement:
$image = imagecreatefromjpeg($fileContent);
The variable $fileContent should be a file name -- but it's the
contents of the file that the function uses. So, what's the
difference between a filename and its contents? Is there a header I
should add? Or does the routine require a read operation?
I'll look at some other functions.
Thanks for your help.
tedd
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