Al wrote:
John Nichel wrote:
Carl Furst wrote:
Ok I am so stumped.. I'm doing something stupid and I can't figure it
out..
Here's the code:
<?php
$eml = 'hiddenemailadddress@xxxxxxxxxxxxxxxx
ceo';
if (strpos($eml, ' ')) echo "yep, there are spaces\n"; //does strpos
see the
spaces?
echo preg_replace('/\s/', '', $eml); //WTF? Preg_replace does not?
echo "$eml\n";
?>
As you can see there are a bunch of spaces in that email address. I'm
trying
to use preg_replace to get rid of them. Strpos sees the spaces and
the first
echo statement is executed. The second echo prints nothing and the third
prints the original $eml with nothing substituted.
Can anyone see why the perl reg isn't seeing the spaces?
Carl
Working fine on my end (copy/pasted your code)
$eml= trim($eml);
$pattern= "%\s%"; //I use % as delimiters, more obvious for
me when debugging
if(preg_match($pattern, $eml) echo "yep, there are spaces\n";
preg_replace($pattern, '', $eml); echo "works now\n";
Sorry, left off the new $eml
$eml= preg_replace($pattern, '', $eml); echo "works now\n";
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