I tested this with
$t = "string string";
preg_replace('/\s/', '', $t);
echo $t;
And the replace left a space... so then I tried this
$t = "string string";
$t = preg_replace('/\s/', '', $t);
echo $t;
And the output was spaceless (spaced out?)... maybe worth a try?
HTH
Dan
--
-----Original Message-----
From: Al [mailto:news@xxxxxxxxxxxxx]
Sent: 17 January 2006 22:45
To: php-general@xxxxxxxxxxxxx
Subject: Re: Help with regular expressions
John Nichel wrote:
> Carl Furst wrote:
>
>> Ok I am so stumped.. I'm doing something stupid and I can't figure it
>> out..
>>
>> Here's the code:
>>
>> <?php
>>
>> $eml = 'hiddenemailadddress@xxxxxxxxxxxxxxxx ceo';
>> if (strpos($eml, ' ')) echo "yep, there are spaces\n"; //does strpos
>> see the
>> spaces?
>> echo preg_replace('/\s/', '', $eml); //WTF? Preg_replace does not?
>> echo "$eml\n";
>>
>>
>> ?>
>>
>> As you can see there are a bunch of spaces in that email address. I'm
>> trying
>> to use preg_replace to get rid of them. Strpos sees the spaces and the
>> first
>> echo statement is executed. The second echo prints nothing and the third
>> prints the original $eml with nothing substituted.
>>
>> Can anyone see why the perl reg isn't seeing the spaces?
>>
>> Carl
>>
>
> Working fine on my end (copy/pasted your code)
>
$eml= trim($eml);
$pattern= "%\s%"; //I use % as delimiters, more
obvious for me when debugging
if(preg_match($pattern, $eml) echo "yep, there are spaces\n";
preg_replace($pattern, '', $eml); echo "works now\n";
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