Re: Re: Strange notation to create object

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On Thu, 2005-06-23 at 15:28, Matthew Weier O'Phinney wrote:
> * Robert Cummings <robert@xxxxxxxxxxxxx> :
> > On Thu, 2005-06-23 at 13:36, Matthew Weier O'Phinney wrote:
> > > * Robert Cummings <robert@xxxxxxxxxxxxx> :
> > > > On Thu, 2005-06-23 at 11:32, Matthew Weier O'Phinney wrote:
> > > > > The above notation is unnecessary when developing in PHP5, as objects in
> > > > > PHP5 are passed by reference by default. However, in PHP4, this was
> > > >
> > > > Not entirely, there's still a subtle difference in PHP5 between
> > > > assigning an object with = versus assigning with = &.
> > > 
> > > Would you mind explaining the difference? I've seen nothing in the docs,
> > > to indicate that assigning objects with =& in PHP5 is necessary, or even
> > > desired. My experience with PHP5 hasn't shown this either. I'd be
> > > interested to know to what you refer.
> >
> > See for yourself when running the following script:
> >
> > <?php
> >
> >     class a
> >     {
> >     }
> >
> >     class b
> >     {
> >     }
> >
> >     $aObj = new a();
> >     $bObj = new b();
> >
> >     $foo1 = $aObj;
> >     $foo2 = $aObj;
> >     $foo3 = $foo1;
> >     $foo4 = &$foo2;
> >
> >     echo "------------------\n";
> >     print_r( $foo1 );
> >     print_r( $foo2 );
> >     print_r( $foo3 );
> >     print_r( $foo4 );
> >
> >     $foo1 = $bObj;
> >     $foo2 = $bObj;
> >
> >     echo "------------------\n";
> >     print_r( $foo1 );
> >     print_r( $foo2 );
> >     print_r( $foo3 );
> >     print_r( $foo4 );
> >
> >     $foo1 = &$aObj;
> > ?>
> 
> This doesn't demonstrate what the OP was talking about, which is initial
> assignment of an object using a reference operator. The results of this
> make perfect sense to me -- the references are passed exactly as I would
> expect. 
> 
> Let me rephrase my question to you: is there a reason to do the initial
> object assignment using a reference operator using PHP5? I.e., is there
> a good reason to do this:
> 
>     $foo =& new Foo();
> 
> instead of:
> 
>     $foo = new Foo();
> 
> I haven't seen any reason to do the former case using PHP5.

Your original response said that the above notation was unneccessary, I
took that to mean the & operator for reference. Looking back I see ow
that your comment was ambiguous, and I agree there is no need for the &
when assigning a new object. I was merely clarifying that references and
normal assignment are not synonymous for objects in PHP 5.

Cheers,
Rob.
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