Re: filtering out array values

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



On Tuesday 02 November 2004 13:32, Merlin wrote:

> I am retrieving some values out of the db and would only like to show those
> available inside a drop down field. Now I do have 2 arrays which fill the
> drop down field and one array with the values which should only show up.
>
> Example:
> $objects_available = array(3,5,7);
>
>
> $ob_options = array( 'all available', 'accomodations', 'internet access',
> 'tour operators', 'restaurants' , 'pubs', 'clubs', 'museums', 'secret
> spots', 'hotels at the airport');
>
> $ob_values = array(  0, 1, 2, 3, 4, 5, 6, 7, 8, 9);
>
> Has anybody an idea how to filter just the ones out which are inside the
> objects available array? I am sure this  is possible without any if
> statements, but just cant come up with a clear programming solution.

Assuming that '0' corresponds to 'all available', '1' to 'accomodations' etc, 
then:

  foreach ($objects_available as $key) {
    echo $ob_options[$key];
 }

-- 
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
------------------------------------------
Search the list archives before you post
http://marc.theaimsgroup.com/?l=php-general
------------------------------------------
/*
There are three kinds of people: men, women, and unix.
*/

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php


[Index of Archives]     [PHP Home]     [Apache Users]     [PHP on Windows]     [Kernel Newbies]     [PHP Install]     [PHP Classes]     [Pear]     [Postgresql]     [Postgresql PHP]     [PHP on Windows]     [PHP Database Programming]     [PHP SOAP]

  Powered by Linux