2006/10/3, Charley Tiggs <lists@xxxxxxxxx>:
ben wilko wrote:
> Hi Guys
>
> I am printing names into a combo box and posting the variable. I try and use the
> name ($Sem) in an SQL statement; WHERE name = $Sem; but I get an error which is
> displayed near the end of this message. Are we able compare php string to
> postgresql character varying?? not sure how else to do the selection
>
>
> $conn = pg_Connect("host=localhost dbname=#### user=#### password=####");
> if (!$conn) {echo "An database connection error occurred.\n"; exit;}
>
>
> // e.g. $Sem = "seminar one";
>
> $Sem = $_POST['Seminars'];
>
>
> $Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name = $Sem");
> if (!$SemNo) {echo "A query error occurred in retreiving the selected seminar's
> ID <br>"; /*exit;*/}
> $Sem_No = pg_Result($Sem_No, 0);
>
I think you should try:
$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name =\"$Sem\"");
OR
$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name ='$Sem'");
OR
$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name
='".$Sem."';";);
or something like this for escape "seminar one" with " " inside the sql query
But i look the table description you still compare a integer row with
a string row
try maki the query like this:
$Sem_No = pg_Exec($conn,"SELECT name FROM seminar WHERE name =
'$Sem'");
> // Error Message
>
> *Warning*: pg_exec() [function.pg-exec
> <http://www.citanalyst.com/jet/form/function.pg-exec>]: Query failed: ERROR:
> syntax error at or near "one" at character 54 in
> */home/bdwilko/public_html/jet/form/insertP.php* on line *56*
> A query error occurred in retreiving the selected seminar's ID
>
Make sure that you're quoting the value you want to compare. At a quick
glance, this where the error is:
$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name = $Sem");
should be:
$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name =
'$Sem'");
To be more accurate, you should probabley do:
$Sem = pg_escape ( $Sem );
$Sem_No = pg_Exec($conn,"SELECT seminar_id FROM seminar WHERE name =
'$Sem'");
Charley
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