thanks walid for your attantions...
i dont understand wich method i use to import the picture, but i can tell this is a php script was i create:
1. upload.php -- for upload file....
<html>
<head>
<title>Daftar File</title>
</head>
<body>
<center>
<p><h3>Daftar File Di Dalam Tabel UPLOAD</h3></p>
<font size=5>
<?php
$konek = "host=server.amq.org dbname=latihan user=postgres password=postgres";
$dbh = pg_connect($konek);
if (!$dbh) {
echo "Koneksi ke Database PostgreSQL tidak berhasil";
exit;
}
$sql = "SELECT id, name, picoid, adddate FROM pic";
$hasil = pg_exec($dbh, $sql);
$row = pg_numrows($hasil);
for ($i=0; $i<$row; $i++)
{
$data = pg_fetch_row($hasil);
echo $data[0].' - <a href="detail.php?id='.$data[0].'" target="_blank"'."> $data[1] </a><br>";
}
?>
<br><hr>
<h3>Upload File</h3>
<form id="data" method="post" action="input_file.php"
enctype="multipart/form-data">
<p><font size=3><b>Pilih File yang ingin di Upload</b></font></p>
<input name="testfile" type="file" size="50" maxlength="100000"><br><br>
<input name="submit" type="submit" value="KIRIM">
</form> </font> </center> </body> </html>
2. input_file.php
<?php
$konek = "host=server.amq.org dbname=latihan user=postgres password=postgres";
$dbh = pg_connect($konek);
if (!$dbh) {
echo "Koneksi ke Database PostgreSQL tidak berhasil";
}
// check file upload
if ($testfile)
{
if (is_uploaded_file ($testfile))
{
chmod ($testfile, 0777);
//query for upload file in to database
$sql = "INSERT INTO pic (name, picoid) VALUES";
$sql .= "('$testfile_name', lo_import('$testfile'))";
$hasil = pg_exec($dbh, $sql);
if (!$hasil)
{
echo "File yang dimaksud tidak berhasil di UPLOAD<br><br><br>";
exit;
}
else
{
echo "<h1>File <b>$testfile_name</b> BERHASIL di UPLOAD</h1><br> ";
}
}
else
{
echo "Tidak ada File yang telah di UPLOAD";
}
}
pg_close($dbh);
?>
3. detail.php -- for display the image.
<?php
$konek = "host=server.amq.org dbname=latihan user=postgres password=postgres";
$dbh = pg_connect($konek);
if (!$dbh) {
echo "Koneksi ke Database PostgreSQL tidak berhasil";
exit;
}
$sql = "SELECT id, name, picoid, adddate FROM pic WHERE id=$id";
$hasil = pg_exec($dbh, $sql);
$data = pg_fetch_row($hasil, 0);
if (!$data)
{
echo "Tidak ditemukan file yang dimaksud";
}
else
{
Header ("Content-type: image/png");
pg_exec($dbh, "BEGIN");
$ofp = pg_loopen($data[2], "r");
if (!$ofp)
{
echo "File Tersebut Tidak Dapat Diakses";
}
$img = pg_loreadall($ofp);
print $img;
pg_loclose($ofp);
pg_exec($dbh, "END");
}
?>
where syntax from the php script on top, make the problem ???
i hope all of you unnderstand my questions....
utomo
indonesia
> hello
> sorry for my english, which method tou use to import the picture?
> Walid
> Le Vendredi 27 Juin 2003 11:29, vous avez écrit :
> > Dear all,
> >
> > any body can help my problem, i am very look forward to invite my problem.
> > first, i was create one tabel (the table name is "pic") and i was insert 4
> > image on the table. look the table like this :
> >
> > latihan=# SELECT * FROM pic ;
> > id | name | picoid | adddate
> > ----+-------------+--------+-------------------------------
> > 1 | gbr_001.png | 72591 | 2003-06-26 15:04:45.621274+07
> > 2 | gbr_004.png | 72593 | 2003-06-26 15:11:24.881415+07
> > 3 | browse.png | 72595 | 2003-06-26 15:29:04.423781+07
> > 4 | bird.jpg | 72597 | 2003-06-27 13:24:33.160357+07
> > (4 rows)
> >
> > i was create the php skrip for display the image on browser, the php skrip
> > from book "Advance Web Programming PHP-Postgresql" the author is Ewald,
> > etc: 1. upload.php
> > 2. input_file.php
> > 3. detail.php
> >
> > for upload file to database postgres no problem, but.....
> > when i display the image from browser i found error like this :
> >
> > The image http://server.amq.org/~andhie/book/detail.php?id=4 cannot be
> > displayed, because it contains errors.
> >
> > please help me, how i can do this.
> >
> > best regards
> >
> > utomo
> > indonesia
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