Re: syntax for option select

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this syntax php with postgresql ....
this syntax still wrong / error 
in my form doesn't list ... 


<th width="20%" align="left" nowrap>Kode Fakultas</th>
  <td width="72%"><select name="kode_fak">select kode_fak<option>
<?php
	$query1="select kode_fak, nama_fak from fakultas";
	$query_result1 = pg_query($conn, $query1);
   	while ($row1 = pg_fetch_array($query_result1))
	{
        	echo "<option
value=\"$row1[kode_fak]"\>$row1[nama_fak]</option>\n";
   	}

?>
</select>
</td>


table in postgresql 


CREATE TABLE FAKULTAS (KODE_FAK CHAR (1)NOT NULL,
			NAMA_FAK VARCHAR (50),
			NAMA_FAK_EN  VARCHAR (50),
			CONSTRAINT XPKFAKULTAS
			PRIMARY KEY (KODE_FAK));
help me please ...
thank's 
newbie php-postgresql

 

> 
> * Ahmad Sentri <sentri@xxxxxxxxxxx> [25.03.2003 18:18]:
> > 
> > hii ..
> > 
> > i want make a form list
> > and my data list from one colom in a table 
> > i had create table faculty
> > and a field in this table was kode_fakulty,name_fakulty
> > 
> > and in my form list i want list my kode_fakulty from table fakulty
> > in php-postgresql i was try to create these syntax 
> > so ...
> > 
> > if we run my localhost in webserver 
> > always syntax error or my list can't contain data 
> > 
> > thank's 
> > newbie in php-postgresql
> 
> Please, give full CREATE TABLE statement for your table.
> Also, part of your PHP script, that generates error is needed.
> 
> -- 
> 
> Victor Yegorov
> 



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