Re: synchronization between two process without lock

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On Thu, Aug 24, 2017 at 02:30:41AM +0800, Yubin Ruan wrote:
> Hi paul,
> 
> 2017-08-08 10:12 GMT+08:00 Yubin Ruan <ablacktshirt@xxxxxxxxx>:
> > 2017-08-08 0:57 GMT+08:00 Paul E. McKenney <paulmck@xxxxxxxxxxxxxxxxxx>:
> >> On Tue, Aug 08, 2017 at 12:48:08AM +0800, Yubin Ruan wrote:
> >>> 2017-08-05 9:02 GMT+08:00 Yubin Ruan <ablacktshirt@xxxxxxxxx>:
> >>> > 2017-08-05 3:50 GMT+08:00 Paul E. McKenney <paulmck@xxxxxxxxxxxxxxxxxx>:
> >>> >> On Fri, Aug 04, 2017 at 11:57:28PM +0800, Yubin Ruan wrote:
> >>> >>> 2017-08-04 22:52 GMT+08:00 Yubin Ruan <ablacktshirt@xxxxxxxxx>:
> >>> >>> > Hi,
> >>> >>> > I am sure the subject explain my intention. I got two processes trying
> >>> >>> > to modifying the same place. I want them to do it one after one, or,
> >>> >>> > if their operations interleave, I would like to let them know that the
> >>> >>> > content have been changed and polluted by the other so that the
> >>> >>> > content should be given up. That is, I would rather give up the data,
> >>> >>> > if polluted, than having a false one.
> >>> >>> >
> >>> >>> > I try to set a atomic ref counter, but it seems impossible to do that
> >>> >>> > without a lock to synchronize.
> >>> >>> >
> >>> >>> > Note that I don't want a strict synchronization: the situation is a
> >>> >>> > lot better. The data can be given up if that place has been polluted.
> >>> >>>
> >>> >>> Let's explain some of my reasoning: if process A use some flag to
> >>> >>> indicate that it has entered the critical region, then if it crash
> >>> >>> before it can reset the flag, all following processes cannot enter
> >>> >>> that region. But if process A cannot use flag for indication, how to
> >>> >>> other people know (how to synchronization)?
> >>> >>
> >>> >> The simplest approach is to guard the data with a lock.
> >>> >
> >>> > Indeed. But if a process get killed then it will have no chance to release
> >>> > the lock...
> >>> >
> >>> > By the way, do you know whether there are any chances that a thread get
> >>> > killed by another thread when doing some "small" things? I mean something
> >>> > like this:
> >>> >
> >>> >     lock();
> >>> >     some_mem_copying();
> >>> >     unlock();
> >>> >
> >>> > Are there any chance that a thread get killed by another thread before it
> >>> > can "unlock()", without the entire process going down?
> >>
> >> Indeed, that is possible.  The pthread_kill() system call if nothing
> >> else.
> >>
> >>> pthread_mutexattr_setrobust(..) will help in this situation, although it is
> >>> quite painful that nobody is maintaining the NPTL docs currently and you have
> >>> to dive into the source code if you want to make sure the semantic is exactly
> >>> what you want.
> >>
> >> True on all counts.  But what exactly are you trying to achieve?
> >
> > What I am going to achieve is to allow multiple producer to place some content
> > in some slots of a queue. The risk is that some producers might be in the same
> > slot, so that it require some locking to synchronize them. But if you use lock,
> > a thread holding the lock can get killed accidentally (for whatever reasons)
> > before releasing it, causing all the other producers unable to acquire it
> > therefore.
> 
> I got a really great idea for this kind of task. I want to share it with you:
> 
> The case:
> I got a piece of memory(several Kb), and multiple producers try to put content
> into that area. A (single) consumer would try to read the content. So there
> are two kind of synchronization: synchronization between producers and
> synchronization between consumer and producers.(Note that there is only one
> consumer, while a lots of producers)
> 
> I don't want that single consumer to read intermediate data or dirty data so
> that I need some synchronization mechanism to guarantee that consumer read
> after a producer have finished putting content into that place. Also, I don't
> want multiple producers to write to that place at the same time, since that
> will result in dirty data.
> 
> Clearly we do not need any lock between consumer and producer, a single flag
> would suffice. But for synchronization between producers, we need lock. The
> algorithm can be represented as follow:
> 
>     //consumer
>     if (flag == DATA_IS_CLEAN) {
>         consumer_read_data();
>         flag = DATA_READED; // set it back so that producer can put
> content there after
>     } else {
>         spin_or_return();
>     }
> 
>     // for every producer
>     if (flag == DATA_READED) { // consumer have finished reading
>         if (try_lock()) {
>             put_content();
>             unlock();
>         } else {
>             return;
>         }
>     } else {
>         return;
>     }
> 
> so now we have the needed synchronization.
> 
> But the problem is, a producer can simple die after it does
> `put_content()` and before
> `unlock()`. That is awkward, since that effectively means deadlock for
> that memory area.
> 
> To rescue, we can use a robust lock from pthread, which guarantees
> that if the lock
> holder dies, the next one who tries to acquire the lock will succeed.
> (see pthread_mutexattr_setrobust(3))
> 
> Pthread's robust lock is great, and is very fast. However, I still
> consider it a litte
> bit heavy and I want to craft my own. I want to make it lock free,
> with some atomic
> instruction. So I come up with a idea: I can use a atomic `xadd'
> instruction for that.
> I can implement my own `try_lock()' like this:
> 
>     int try_lock() {
>         uint8_t previous_value = xadd(&lock, 1);
>         return previous_value == 0;
>     }
> 
> Clearly when *lock == 0, some process can xadd it to 1 and
> successfully acquire the lock.
> A correspondingly simple `unlock()' would be:
> 
>     int unlock() {
>         *lock = 0;
>     }
> 
> Now how do we deal with the deadlock problem? Use wrap around. Because
> every process who
> tries to acquire the lock will xadd 1 to the lock, until some time it
> wrap around and we
> now reach 0 again, which will atomically unlock the lock!! Therefore,
> if the lock owner
> dies, the lock will be unlocked some time.
> 
> You may ask, what if the lock get wrapped around "too fast" such that
> two process hold the
> lock at the same time? The answer is, make the lock of some bigger
> type, probably uint32_t,
> in which case you have to have 2^32 processes on a system (at the same
> time) to complete
> for that lock, in such a short time(as we are some quick thing inside
> the critical region).
> That would make the race impossible. In my case, because I have a long
> queue, and it takes
> many processes to occupy a queue to reach the original one, a uint8_t
> will suffice.
> 
> (I am designing some lock-free multi-producers single-consumer message
> queue. The design is
> pretty nice. I will send more later ;-)

This has been a very popular activity over the past few decades.
Here are a few places you can look to see other work in this area:

http://libcds.sourceforge.net/
http://liburcu.org
https://github.com/concurrencykit/ck

There are quite a few others.

The difficulty with breaking locks is that the state space is quite
large, and can vary based on things like compiler optimizations.
Don't get me wrong, people really do things like this, but it is
not easy.

							Thanx, Paul

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