> The difference here I think is not between 0 & NULL subtracting 4 or 8 from base pointer,rbp is not a talk abt difference of zero and NULL as we saw both times it was zero which was moved > > movq $0, -8(%rbp) <------------ > > movl $0, -4(%rbp) <------------- > but between an integer & a pointer. Exactly kishore, thatz what it is !!!! :) > On a 64 bit system while > int is still 4 bytes, the pointer could be (because I had read > somewhere that some 64 bit archs use 32 bit pointers > in some cases) 8 bytes. -- Kernelnewbies: Help each other learn about the Linux kernel. Archive: http://mail.nl.linux.org/kernelnewbies/ FAQ: http://kernelnewbies.org/faq/
