Sorry I meant non-routable. Routers on the internet are meant to ignore those addresses. 10.x/8 192.168.x/16 172.16.x/20 ------Original Message------ From: Amos Jeffries To: nullv@xxxxxxx Cc: Ethy H. Brito Cc: netfilter-owner@xxxxxxxxxxxxxxx Cc: Al Grant Cc: netfilter Subject: Re: IPTables Sent: Apr 14, 2012 11:35 AM On 14/04/2012 11:54 a.m., nullv@xxxxxxx wrote: > It can't be. it's a link-local address The difference between IPv4 and IPv6. IPv4 has no link-local limitation outside of 127.0.0.0/8 built into the hardware, it *can* leak into the WAN if you configure things non-standard. AYJ > ------Original Message------ > From: Ethy H. Brito > > On Wed, 11 Apr 2012 15:03:46 +1200 > Al Grant wrote: > >> Hiya All, >> >> I am after a little guidance please on the following problem: >> >> My topology is as follows: >> >> inet----router 192.168.1.254-------wlan0 192.168.1.71&& eth0 >> 192.168.70.121------ip camera 192.168.70.140:80 >> >> Note: >> >> (1) eth0 and wlan0 are on a PC running Ubuntu. >> >> (2) Port 5555 on the router is forwarded to 80 on 192.168.1.71 >> >> (2) in sysctl I have set sysctl net.ipv4.ip_forward=1 >> >> Now what I need to do is to be able to access the IP camera from the >> inet. >> >> So I have tried adding IPTables: >> >> iptables -t nat -A PREROUTING -i wlan0 -d 192.168.1.71 -p tcp --dport >> 5555 -j DNAT --to 192.168.70.140:80 >> >> Now this should allow me to access the camera by pointing a web >> browser to the real world public ip on port 5555, however I get page >> cannot be displayed. > Hi > > just to be sure: 192.168.1.71 is NOT your "real world public ip", is it? > > Ethy > -- > To unsubscribe from this list: send the line "unsubscribe netfilter" in > the body of a message to majordomo@xxxxxxxxxxxxxxx > More majordomo info at http://vger.kernel.org/majordomo-info.html > > N‹§²æìr¸›yúèšØb²X¬¶Ç§vØ^–)Þº{.nÇ+‰·§z×â–׫Š{ayºÊ‡Ú™ë,j¢f£¢·hš‹àz¹®w¥¢¸¢·¦j:+v‰¨ŠwèjØm¶Ÿÿ¾«‘êçzZ+ƒùšŽŠÝ¢j"?ú!tml= ÿôèº{.nÇ+‰·Ÿ®‰†+%ŠËÿ±éݶ¥Šwÿº{.nÇ+‰·§z×â–׫þ)í…æèw*jg¬±¨¶‰šŽŠÝ¢jÿ¾«þG«?éÿ¢¸¢·¦j:+v‰¨ŠwèjØm¶Ÿÿþø¯ù®w¥þŠàþf£¢·hš?â?úÿ†Ù¥