> Let me try and understand this. > > R is routing between 192.168.1.0/24 and 10.232.18.0/24. > As A is on the 192.168.1.0/24 side of R. > But to give A an 10.232.18.0/24 address (dynamically)? > > Why? > For some clients , R should act as a mere bridge , Not a router . On Wed, Jun 30, 2010 at 8:07 AM, Simon Horman <horms@xxxxxxxxxxxx> wrote: > On Mon, Jun 28, 2010 at 03:43:46PM +0530, ratheesh k wrote: >> Hi, >> >> A -------> R ------->S >> >> I have a linux machine A is connected to Linux machine R . Machine R >> is having two network interfaces and acting as a router . >> It has a dhcp server running . It will assign ip in 192.168.1.0/24 >> subnet to all machine connected on lan side ( A is connected also in >> lan side ) . Wan side of R is connected to HTTP server S . There is >> also a DHCP server running on S to assign ip in 10.232.18.0/24 subnet >> . Is there any way , in which NAT should be bypassed to get ip from >> DHCP server running on S . My question is : How can A will get an ip >> from 10.232.18.0/24 pool ip .? >> ebtables is an option ? How can we make it ? >> Is there any other optimal way ? > > Let me try and understand this. > > R is routing between 192.168.1.0/24 and 10.232.18.0/24. > As A is on the 192.168.1.0/24 side of R. > But to give A an 10.232.18.0/24 address (dynamically)? > > Why? > > -- To unsubscribe from this list: send the line "unsubscribe netfilter" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
