OK - I did that (can't believe I missed that...) :-/ However, now I have something else weird happening. I can successfully ping out to hosts that are on my "public" network (our /26 net that the ISP gives us.) However, I can't seem to get past the router, and the tracert looks weird: C:\>tracert -d 207.157.9.151 Tracing route to 207.157.9.151 over a maximum of 30 hops 1 <1 ms <1 ms <1 ms 10.227.1.1 2 1 ms 1 ms 1 ms 10.200.227.1 3 3 ms 3 ms 3 ms 10.1.2.41 4 4 ms 4 ms 4 ms 207.157.9.151 I never see either interface that is in the firewall/NAT box. It goes straight from the router that is at the core (10.1.2.41) to the "public" address on our subnet. Weird. >>> Steve Mickeler <steve@xxxxxxxxxx> 03/18/03 12:59PM >>> On Tue, 18 Mar 2003, Greg Dickinson wrote: > Hello all, > > This question will undoubtedly get me branded as a n00b :-) but I am about to go insane trying to figure this out. Am I doing something wrong? > > Here's the scenario: > > I have a RedHat 8 (Kernel 2.4-18) firewall that I am going to run squid on, as well as do some static NATting for some of the administrative PC's here. I have configured the Cisco router to direct all the traffic from the affected /24 subnet to the linux box, and I am trying to do a 1-to-1 NAT so we can do things like Terminal Services, etc. across the internet. I am using the following commands (the addresses are for my PC) > > iptables -t nat -A POSTROUTING -s 10.227.101.4 -j SNAT --to 207.157.9.<something> > iptables -t nat -A PREROUTING -s 207.157.9.<something> -j DNAT --to 10.227.101.4 Change the -s to -d on the PREROUTING rule. iptables -t nat -A PREROUTING -d 207.157.9.X -j DNAT --to 10.227.101.4 iptables -t nat -A POSTROUTING -s 10.227.101.4 -j SNAT --to 207.157.9.X > > And all the traffic summarily dies at the firewall :-) > > I have aliased the 207.157.9.<something> address to the eth1 interface of the firewall. What simple, obvious thing have I missed? > > TIA, > > --Greg > > > > Gregory B. Dickinson, CNE CCNA > Systems Engineer > Logista Solutions > (205) 231-5602 > (tQ = 2b|!2b) > >
