Re: is_real_interrupt in 8250.c

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Theodore Tso wrote:
On Wed, Nov 29, 2006 at 09:44:59AM -0800, Dan Nicolaescu wrote:
Hi,

In 8250.c is_real_interrupt is defined like this:
/*
 * We default to IRQ0 for the "no irq" hack.   Some
 * machine types want others as well - they're free
 * to redefine this in their header file.
 */
#define is_real_interrupt(irq)  ((irq) != 0)

on my platform the UART IRQ is 0, so is_real_interrupt returns
false.

In order to allow machines to override is_real_interrupt, and for the
code to match the comment shouldn't this patch be applied?

No, IRQ 0 for linux is always "no IRQ".  We should probably add this
to the LKML FAQ, since it keeps coming up.  Per Linus, if there are
any architectures that has a valid IRQ #0, then the
architecture-specific kernel code should remap IRQ numbers.  See:

	http://comments.gmane.org/gmane.linux.kernel/468449

						- Ted
My reading of the messages you linked to is that is_real_interrupt should eb defined as

#define is_real_interrupt(irq) ((irq) != NO_IRQ)

where NO_IRQ may be defined differently for platforms where IRQ #0 is valid,
not that IRQ 0 is always "no IRQ"

I have not done any low level x86 linux work, but even on an x86 IRQ 0 is valid.





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