Hallo everybody,
I have a serious problem. Could someone help me how to
use netlink socket? I write a small program (attached)
that might read data from the netlink socket. But it
still for me impossible to read anything in that
socket. I don't know what i'm doing wrong.
If you a sample program to do that please send it to
me, i would be very greatful.
PS: I've also used libipq but it wasn't help.
My code:
#include <stdio.h>
#include <sys/socket.h>
#include <sys/types.h>
#include <string.h>
#include <asm/types.h>
#include <linux/netlink.h>
#include <linux/socket.h>
#include <linux/uio.h>
int main(int argc, char** argv)
{
int sockfd, addrlen, len;
unsigned char *buffer;
struct cmsghdr cmsg;
struct iovec iov;
struct sockaddr_nl peer;
struct sockaddr_nl nladdr={
nl_family:AF_NETLINK,
nl_pid : getpid(),
nl_groups: 0
};
struct msghdr msg = {
(void *)&nladdr, sizeof(nladdr),
&iov, 1, NULL, 1024, 0};
memset(&peer, 0, sizeof(struct sockaddr_nl));
peer.nl_family = AF_NETLINK;
peer.nl_pid = 0;
peer.nl_groups = 0;
if ((sockfd = socket(PF_NETLINK,
SOCK_RAW,NETLINK_FIREWALL)) < 0) {
perror("netlink socket");
return -1;
}
if (bind(sockfd, (struct sockaddr *)&nladdr,
sizeof(nladdr))<0){
perror("bind");
return -1;
}
len = sizeof(nladdr);
if (getsockname(sockfd, (struct sockaddr
*)&nladdr,(socklen_t *)&len)<0){
perror("getsockname");
return -1;
}
addrlen = sizeof(peer);
if (recvfrom(sockfd,buffer,1024,0,(struct sockaddr
*)&peer,
(socklen_t *)&addrlen) < 0) {
perror("recvfrom");
return -1;
}
/*
if (recvmsg(sockfd, &msg, 0) < 0) {
perror("recvmsg");
return -1;
}
*/
close(sockfd);
return 0;
}
[root@heghta sebro]# lsmod
Module Size Used by
iptable_nat 18112 0 (unused)
ip_conntrack 20288 1 [iptable_nat]
iptable_mangle 1888 0 (unused)
iptable_filter 1856 0 (unused)
ip_queue 4672 0 (unused)
ip_tables 12800 5 [iptable_nat
iptable_mangle iptable_filter]
3c509 6992 1 (autoclean)
[root@heghta sebro]# iptables -L -t mangle
Chain PREROUTING (policy ACCEPT)
target prot opt source destination
QUEUE icmp -- anywhere anywhere
Thank you for the help.
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