Re: [Patch v2 2/2] mm/page_alloc.c: define node_order with all zero

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On 3/27/20 5:26 PM, Wei Yang wrote:
On Fri, Mar 27, 2020 at 03:37:57PM -0700, John Hubbard wrote:
On 3/27/20 3:01 PM, Wei Yang wrote:
Since we always clear node_order before getting it, we can leverage
compiler to do this instead of at run time.

Signed-off-by: Wei Yang <richard.weiyang@xxxxxxxxx>
---
   mm/page_alloc.c | 3 +--
   1 file changed, 1 insertion(+), 2 deletions(-)

diff --git a/mm/page_alloc.c b/mm/page_alloc.c
index dfcf2682ed40..49dd1f25c000 100644
--- a/mm/page_alloc.c
+++ b/mm/page_alloc.c
@@ -5585,7 +5585,7 @@ static void build_thisnode_zonelists(pg_data_t *pgdat)
   static void build_zonelists(pg_data_t *pgdat)
   {
-	static int node_order[MAX_NUMNODES];
+	static int node_order[MAX_NUMNODES] = {0};


Looks wrong: now the single instance of node_order is initialized just once by
the compiler. And that means that only the first caller of this function
gets a zeroed node_order array...


What a shame on me. You are right, I miss the static word.

Well, then I am curious about why we want to define it as static. Each time we
call this function, node_order would be set to 0 and find_next_best_node()
would sort a proper value into it. I don't see the reason to reserve it in a
global area and be used next time.

It's not just about preserving the value. Sometimes it's about stack space.
Here's the trade-offs for static variables within a function:

Advantages of static variables within a function (compared to non-static
variables, also within a function):
-----------------------------------

* Doesn't use any of the scarce kernel stack space
* Preserves values (not always necessarily and advantage)

Disadvantages:
-----------------------------------

* Removes basic thread safety: multiple threads can no longer independently
  call the function without getting interaction, and generally that means
  data corruption.

So here, I suspect that the original motivation was probably to conserve stack
space, and the author likely observed that there was no concurrency to worry
about: the function was only being called by one thread at a time.  Given those
constraints (which I haven't confirmed just yet, btw), a static function variable
fits well.


My suggestion is to remove the static and define it {0} instead of memset
every time. Is my understanding correct here?


Not completely:

a) First of all, "instead of memset every time" is a misconception, because
   there is still a memset happening every time with {0}. It's just that the
   compiler silently writes that code for you, and you don't see it on the
   screen. But it's still there.

b) Switching away from a static to an on-stack variable requires that you first
   verify that stack space is not an issue. Or, if you determine that this
   function needs the per-thread isolation that a non-static variable provides,
   then you can switch to either an on-stack variable, or a *alloc() function.



thanks,
--
John Hubbard
NVIDIA




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