On Thu, 15 Jan 2009, Chris Mason wrote: > > > > Grr. Different alignment for 64-bit values, coupled with "name" not > > having a size that is a multiple-of-eight. > > Will the fd and the start of the name get aligned differently? I'll fix > it up No, since the name is byte-aligned, the only thing that happens is that the total alignment (which comes from the alignment of __s64) affects the final size - think about having an array of those things, and the "sizeof()" gives you what the offset to the next entry in the array would be. So they'll look _exactly_ the same in all ways, except for padding at the end. Linus -- To unsubscribe from this list: send the line "unsubscribe linux-fsdevel" in the body of a message to majordomo@xxxxxxxxxxxxxxx More majordomo info at http://vger.kernel.org/majordomo-info.html
