Ben, after assign all bitfield struct member, how to pack them to be a
32bit integer value?
DEC BIN
43 101011 -> foo.a (6 bit)
11 1011 -> foo.b (4 bit)
120 01111000 -> foo.c (8 bit)
30 11110 -> foo.d (5 bit)
418 110100010 -> foo.e (9 bit)
the bit pattern is : 10101110110111100011110110100010 or 2933800354 in
decimal, is this possible?
while with masking and shift i can pack them with:
((foo.a & 0x3f) << 26) | ((foo.b & 0xf) << 22) | ((foo,c & 0xff) <<
14) | ((foo.d & 0x1f) << 9) | (foo.e & 0x1ff)
On Sat, Aug 29, 2009 at 12:02 AM, Ben Rosenberg<scdlbx@xxxxxxxxx> wrote:
> Glynn's example of bitfields is cleaner and better than this, but I
> put a basic implementation of bitfields using your parameters at the
> end of this message. From my understanding, the way bitfields are
> implemented in C is with bit shifts and masks, so I don't think there
> is a performance difference between the two.
>
> #include <stdio.h>
>
> struct bitfield {
> unsigned int a:6;
> unsigned int b:4;
> unsigned int c:8;
> unsigned int d:5;
> unsigned int e:9;
> };
>
> int main(void) {
> struct bitfield foo;
> foo.a = 43;
> foo.b = 11;
> foo.c = 120;
> foo.d = 30;
> foo.e = 418;
> printf("%u %u %u %u %u\n",foo.a,foo.b,foo.c,foo.d,foo.e);
> return 0;
> }
>
>
> Ben
>
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