Glynn Clements wrote:
run-time callable version of the function. This switch does not
affect `extern inline' functions.
What would be the purpose of "extern inline"?
I mean, inlining is done by the compiler, and extern is only useful to
tell the linker to resolve references to a variable or function that is
initially defined in another object file.
I tried putting an inline function *definition* in lib.cpp:
inline int foo ( void ) { return 2 ; }
and a *declaration* to that function qualified by extern inline in main.cpp:
# include <cstdio>
extern inline int foo ( void ) ;
int main ( void )
{
printf ( "%d\n", foo () ) ;
}
The session transcript:
$ g++ -c main.cpp lib.cpp
main.cpp:3: warning: inline function ‘int foo()’ used but never defined
$ g++ -o main main.o lib.o
main.o: In function `main':
main.cpp:(.text+0x12): undefined reference to `foo()'
collect2: ld returned 1 exit status
$
So extern for inline functions does not work as for normal functions --
so what is the use of extern inline?
Shriramana Sharma.
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