Re: [PATCH 1/3] drm/i915/perf: rework aging tail workaround

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On Sat, Mar 21, 2020 at 09:44:43PM -0700, Dixit, Ashutosh wrote:
On Sat, 21 Mar 2020 16:26:42 -0700, Dixit, Ashutosh wrote:

On Thu, 19 Mar 2020 15:52:01 -0700, Umesh Nerlige Ramappa wrote:
>
> From: Lionel Landwerlin <lionel.g.landwerlin@xxxxxxxxx>

> @@ -477,16 +468,6 @@ static bool oa_buffer_check_unlocked(struct i915_perf_stream *stream)
>	 */
>	spin_lock_irqsave(&stream->oa_buffer.ptr_lock, flags);
>
>	hw_tail = stream->perf->ops.oa_hw_tail_read(stream);
>
>	hw_tail &= ~(report_size - 1);
>
> @@ -496,64 +477,64 @@ static bool oa_buffer_check_unlocked(struct i915_perf_stream *stream)
>
>	now = ktime_get_mono_fast_ns();
>
> +	if (hw_tail == stream->oa_buffer.aging_tail &&
> +	   (now - stream->oa_buffer.aging_timestamp) > OA_TAIL_MARGIN_NSEC) {
> +		/* If the HW tail hasn't move since the last check and the HW
> +		 * tail has been aging for long enough, declare it the new
> +		 * tail.
> +		 */
> +		stream->oa_buffer.tail = stream->oa_buffer.aging_tail;
> +	} else {
> +		u32 head, tail;
>
> +		/* NB: The head we observe here might effectively be a little
> +		 * out of date. If a read() is in progress, the head could be
> +		 * anywhere between this head and stream->oa_buffer.tail.
> +		 */
> +		head = stream->oa_buffer.head - gtt_offset;
>
> +		hw_tail -= gtt_offset;
> +		tail = hw_tail;
>
> +		/* Walk the stream backward until we find a report with dword 0
> +		 * & 1 not at 0. Since the circular buffer pointers progress by
> +		 * increments of 64 bytes and that reports can be up to 256
> +		 * bytes long, we can't tell whether a report has fully landed
> +		 * in memory before the first 2 dwords of the following report
> +		 * have effectively landed.
> +		 *
> +		 * This is assuming that the writes of the OA unit land in
> +		 * memory in the order they were written to.
> +		 * If not : (╯°□°)╯︵ ┻━┻
>		 */
> +		while (OA_TAKEN(tail, head) >= report_size) {
> +			u32 previous_tail = (tail - report_size) & (OA_BUFFER_SIZE - 1);
> +			u32 *report32 = (void *)(stream->oa_buffer.vaddr + previous_tail);

Sorry, this is wrong. This should just be:

			tail = (tail - report_size) & (OA_BUFFER_SIZE - 1);
			report32 = (void *)(stream->oa_buffer.vaddr + tail);

Otherwise when we break out of the loop below tail is still set one
report_size ahead. previous_tail is not needed. (In the previous version of
the patch this used to work out correctly).

> +
> +			/* Head of the report indicated by the HW tail register has
> +			 * indeed landed into memory.
> +			 */
> +			if (report32[0] != 0 || report32[1] != 0)
> +				break;
> +
> +			tail = previous_tail;
>		}

Actually a couple of further improvements to the loop above are
possible. First there is no reason to start at previous_tail, we can just
start at the aligned hw_tail itself. Therefore the loop becomes:

		while (OA_TAKEN(tail, head) >= report_size) {
			u32 *report32 = (void *)(stream->oa_buffer.vaddr + tail);

			if (report32[0] != 0 || report32[1] != 0)
				break;

			tail = (tail - report_size) & (OA_BUFFER_SIZE - 1);
		}

Further, there is no reason to go back to the head but only to the old
tail. Therefore:

		head = stream->oa_buffer.head - gtt_offset;
		old_tail = stream->oa_buffer.tail - gtt_offset;

		hw_tail -= gtt_offset;
		tail = hw_tail;

		while (OA_TAKEN(tail, old_tail) >= report_size) {
			u32 *report32 = (void *)(stream->oa_buffer.vaddr + tail);

			if (report32[0] != 0 || report32[1] != 0)
				break;

			tail = (tail - report_size) & (OA_BUFFER_SIZE - 1);
		}

Please review and see if these two improvements are possible. Thanks!

I think that this is possible. We could check reports between old_tail and tail to optimize the number of reports we read. I will give this a try.

Thanks,
Umesh
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