> 2016-09-21 20:56 GMT+02:00 Serkan Çoban <cobanserkan@xxxxxxxxx>: > > Then you can use 8+3 with 11 servers. > > Stripe size won't be good: 512*(8-3) = 2560 and not 2048 (or multiple) It's not really 512*(8+3) though. Even though there are 11 fragments, they only contain 8 fragments' worth of data. They just encode it with enough redundancy that *any* 8 contains the whole. _______________________________________________ Gluster-users mailing list Gluster-users@xxxxxxxxxxx http://www.gluster.org/mailman/listinfo/gluster-users
