2016-09-21 14:42 GMT+02:00 Xavier Hernandez <xhernandez@xxxxxxxxxx>: > You *must* ensure that *all* bricks forming a single disperse set are placed > in a different server. There are no 4 special fragments. All fragments have > the same importance. The way to do that is ordering them when the volume is > created: > > gluster volume create test disperse 16 redundancy 4 > server{1..20}:/bricks/test1 server{1..20}:/bricks/test2 > server{1..20}:/bricks/test3 > > This way all 20 fragments from each disperse set will be placed in a > different server. However each server will have 3 bricks and no fragment > from a single file will be stored in more than one brick of each server. Now it's clear. So, at very minimum, EC is good starting from 7+3 (10 servers with 1 brick each) because: 512*(7-3) = 2048 Any smaller combinations would mean less redundancy (6+2) or not optimized stripe size like 512*(5-3)=1024 Is this correct ? And what if I have to add some brick to the current servers or I have to add new servers? Can I add them freely or I have to follow some rules ? _______________________________________________ Gluster-users mailing list Gluster-users@xxxxxxxxxxx http://www.gluster.org/mailman/listinfo/gluster-users