On 2007.11.05 23:18:36 +0000, Johannes Schindelin wrote:
> Hi,
>
> On Mon, 5 Nov 2007, Bj?rn Steinbrink wrote:
>
> > On 2007.11.05 13:57:53 -0500, Kristian H?gsberg wrote:
> >
> > > The shell script just has
> > >
> > > case "$all,$interactive,$also,$#" in
> > > *t,*t,*)
> > > die "Cannot use -a, --interactive or -i at the same time." ;;
> > >
> > > which doesn't seem to care about the value of $also. As far as I
> > > understand git commit, it doesn't make sense to pass any of -a, -i, -o
> > > or --interactive at the same time so I guess I could join the checks
> >
> > Note that there are only two commas. The asterisks catch everything and
> > $# won't be "t", so that catches anything with at least two t's.
>
> So shouldn't it be
>
> if (!!all + !!interactive + !!also > 1)
>
> Hmm?
Ah, yeah, that's the short and sweet version, I always forget about the
conversion to bool giving you 0/1 values... ;-)
Note though, that Kristian had a similar check at the end of his email,
that included "only" (but lacked the bool conversion). The original
reason why I thought that it would be better was that for example
"git commit --all --only foo" didn't care about "only" at all. But that
actually was because the --all + paths usage check was broken. So the
fixed version actually refuses to use accept that, but with a (IMHO) not
so good error message:
$ git commit -a -o file
Paths with -a does not make sense.
Given that some people are used to just pass -a all the time, they might
just automatically pass it together with -o. And I think that we
actually want to tell them that -a + -o makes no sense instead. Just
like we do for -a + -i, which is kind of the complementary usage error.
So I'd go for a correct version of Kristian's suggestion:
if (!!also + !!only + !!all + !!interactive > 1)
die("Only one of --include/--only/--all/--interactive can be used.");
Björn
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