On Fri, Oct 18, 2019 at 08:07:34AM -0500, Segher Boessenkool wrote: > memset is a reserved name. If you use it you are implementing part of > the standard library (except when using -ffreestanding, but GCC has an > exception there). Right. memset() is reserved by the stdlib. I find it somewhat surprising to get into trouble with it when I explicitly specify the -nostdlib option. -- Josef Wolf jw@xxxxxxxxxxxxx
