On 17 November 2014 16:22, Luchezar Belev <lukcho@xxxxxxxxx> wrote: > hi, > > when i try to compile this c code: > long long t = 2684354560; > gcc (version 4.8.2) says: " ...warning: this decimal constant is > unsigned only in ISO C90 [enabled by default]" > > i added the option -std=C90 but i still get the same warning. > Is there a way one can get rid of this warning (other than adding the > "u" suffix to the literal, which i can't do for complicated reasons > that are beyond this question) The right thing to do is use an ll suffix. long long t = 2684354560ll; > I wonder why does gcc give such warning at all given that in either > standard the literal decimal number "2684354560" is valid: > a) in ISO C90 it will be interpreted as unsigned long and > b) in ISO C99 it will be interpreted as signed long long The fact it means different things in different cases is why you get a warning.
