Re: fuse multiple ops into one new op

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On Fri, 1 Aug 2014, Cherry Vanc wrote:

I need to fuse multiple instructions into a single one.
...
r1 = (r1) op1 (const)
...
...
r1 = (r1) op2 (r2)
...
...
r3 = op3 (r1)
...

I defined a peephole2 pattern in my GCC backend .md file. If these
three instructions are contiguous, then I do get my test "testnew"
instruction. If these instructions are far apart, I dont.

(define_peephole2
 [(set (match_operand:DI 0 "register_operand" "")
   (op1:DI (match_dup 0) (match_operand:SI 1 "immediate_operand" "") ))
 (set (match_dup 0)
   (op2:DI (match_operand:DI 2 "register_operand" "") (match_dup 0)))
 (set (match_dup 0)
   (sign_extend:DI (op3:SI (match_dup 0))))]
 "TARGET_MYCORE"
 [(set (match_dup 0) (sign_extend:DI (op3:SI (op2:SI (op1:SI
(match_dup 0) (match_dup 1)) (match_dup 0)))))]
 "")

(define_insn "*testnew"
 [(set (match_operand:DI 0 "register_operand" "=d")
       (sign_extend:DI (op3:SI (op2:SI (op1:SI (match_dup 0)
(match_operand:SI 1 "immediate_operand" "I")) (match_dup 0)))))]
 "TARGET_MYCORE"
 "testnew 36"
 [(set_attr "mode" "DI")])

How can I fuse multiple instructions that are far apart into a new
single opcode that MYCORE has ?

Hello,

I probably haven't looked closely enough, but could you explain why the 'combine' pass isn't already doing what you want?

--
Marc Glisse




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